JEE MAIN - Physics (2022 - 29th July Morning Shift - No. 25)
A closely wounded circular coil of radius 5 cm produces a magnetic field of $$37.68 \times 10^{-4} \mathrm{~T}$$ at its center. The current through the coil is _________A.
[Given, number of turns in the coil is 100 and $$\pi=3.14$$]
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3
Објашњење
$$B = {{{\mu _0}nI} \over {2R}}$$
$$37.68 \times {10^{ - 4}} = {{4\pi \times {{10}^{ - 7}}100\,I} \over {2 \times 5 \times {{10}^{ - 2}}}}$$
$$I = {{300\,A} \over {100}}$$
$$ = 3\,A$$